3[7x-4(x+3)]+34=16

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Solution for 3[7x-4(x+3)]+34=16 equation:


Simplifying
3[7x + -4(x + 3)] + 34 = 16

Reorder the terms:
3[7x + -4(3 + x)] + 34 = 16
3[7x + (3 * -4 + x * -4)] + 34 = 16
3[7x + (-12 + -4x)] + 34 = 16

Reorder the terms:
3[-12 + 7x + -4x] + 34 = 16

Combine like terms: 7x + -4x = 3x
3[-12 + 3x] + 34 = 16
[-12 * 3 + 3x * 3] + 34 = 16
[-36 + 9x] + 34 = 16

Reorder the terms:
-36 + 34 + 9x = 16

Combine like terms: -36 + 34 = -2
-2 + 9x = 16

Solving
-2 + 9x = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 9x = 16 + 2

Combine like terms: -2 + 2 = 0
0 + 9x = 16 + 2
9x = 16 + 2

Combine like terms: 16 + 2 = 18
9x = 18

Divide each side by '9'.
x = 2

Simplifying
x = 2

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